$title Alkylation Process Optimization (PROCESS,SEQ=20) $onText Optimization of a alkylation process. Bracken, J, and McCormick, G P, Chapter 4. In Selected Applications of Nonlinear Programming. John Wiley and Sons, New York, 1968. Keywords: nonlinear programming, alkylation process, chemical engineering $offText Positive Variable olefin 'olefin feed (bpd)' isor 'isobutane recycle (bpd)' acid 'acid addition rate (1000lb per day)' alkylate 'alkylate yield (bpd)' isom 'isobutane makeup (bpd)' strength 'acid strength (weight pct)' octane 'motor octane number' ratio 'isobutane makeup to olefin ratio' dilute 'acid dilution factor' f4 'f-4 performance number'; Variable profit rangey rangem ranged rangef; Equation yield 'alkylate yield definition' rngyield 'ranged alkylate yield definition' makeup 'isobutane makeup definition' sdef 'acid strength definition' motor 'motor octane number' rngmotor 'ranged motor octane number' drat 'isobutane to olefin ratio' ddil 'dilution definition' rngddil 'ranged dilution definition' df4 'f-4 definition' rngdf4 'ranged f-4 definition' dprofit 'profit definition'; yield.. alkylate =e= olefin*(1.12+.13167*ratio-.00667*sqr(ratio)); makeup.. alkylate =e= olefin + isom -.22*alkylate; sdef.. acid =e= alkylate*dilute*strength/(98-strength)/1000; motor.. octane =e= 86.35 + 1.098*ratio - .038*sqr(ratio) - .325*(89-strength); drat.. ratio =e= (isor+isom)/olefin; ddil.. dilute =e= 35.82 - .222*f4; df4.. f4 =e= -133 + 3*octane; dprofit.. profit =e= .063*alkylate*octane - 5.04*olefin - .035*isor - 10*acid - 3.36*isom; rngyield.. rangey*alkylate =e= olefin*(1.12+.13167*ratio-.00667*sqr(ratio)); rngmotor.. rangem*octane =e= 86.35 + 1.098*ratio - .038*sqr(ratio) - .325*(89-strength); rngddil.. ranged*dilute =e= 35.82 - .222*f4; rngdf4.. rangef*f4 =e= -133 + 3*octane; Model process 'process model with equalities' / yield, makeup, sdef, motor, drat, ddil, df4, dprofit / rproc 'ranged process model' / rngyield, makeup, sdef, rngmotor, drat, rngddil, rngdf4, dprofit /; rangey.lo = .9; rangey.up = 1.1; rangey.l = 1; rangem.lo = .9; rangem.up = 1.1; rangem.l = 1; ranged.lo = .9; ranged.up = 1.1; ranged.l = 1; rangef.lo = .9; rangef.up = 1.1; rangef.l = 1; strength.lo = 85; strength.up = 93; octane.lo = 90; octane.up = 95; ratio.lo = 3; ratio.up = 12; dilute.lo = 1.2; dilute.up = 4; f4.lo = 145; f4.up = 162; olefin.lo = 10; olefin.up = 2000; isor.up = 16000; acid.up = 120; alkylate.up = 5000; isom.up = 2000; olefin.l = 1745; isor.l = 12000; acid.l = 110; alkylate.l = 3048; isom.l = 1974; strength.l = 89.2; octane.l = 92.8; ratio.l = 8; dilute.l = 3.6; f4.l = 145; profit.l = 872; solve process maximizing profit using nlp; solve rproc maximizing profit using nlp;